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...<stdio.h> main() {int a[]={1,2,3,4,5,6,7,8,9,0},*p; p=a; pr...
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I have been trying to understand the output of this program: #include int main(){ static int arr[] = {0, 1, 2, 3, 4}; int *p[] = {arr, arr+1, arr+2, arr+3 ...
1. What will be the output of following program? #include int main() { int a = 5, *b, c; b = &a; printf("%d", a * *b * a + *b); return (0); } Options: 1 ...
Example 1: C Output #include int main() { // Displays the string inside quotations printf("C Programming"); return 0; } Output. C Programming ... To use printf() in our program, we need to include stdio.h header file using the #include statement. The return 0; statement inside the main() function is the "Exit status" of the ...
Consider the C program given below. What does it print? #include <stdio.h> int main () { int i, j; int a [8] = {1, ... $2, 3$ $2, 4$ $3, 2$ $3, 3$
If you the know the subtle difference between (a+1) and *(a+1) this can be solved within 30 seconds. (a+1) → points to the entire 2 nd row. It is a pointer to an integer array of size 5. *(a+1) → points to the 1 st element of the 2 nd row. It is a pointer to an integer.
A main memory contains 32K blocks of 256 words each. A cache memory consists of 128 lines. Calculate the address field bits & draw the lines showi …
Consider the following C program. #include int main { int a[4] [5] = {{1, 2, ... return(0); } The output of the program is _____. Login Register. Dark Mode. Brightness. Profile; Edit Profile; Messages; ... {1,2,3,4,5}. *a = address of 0 th index element of 0 th index of above array i.e address of first element of array(1)
#include void main() { int aa[4][4]={{1,2,3,4},{5,6,7,8},{3,9,10,2},{4,2,9,6}}; int i ,s=0 ; for (i=0;i<4;i++) s+=aa[i][1]; printf("%d\n",s);
这个问题的关键是理解 &a a是一个数组名，也就是数组的首地址。对a进行取地址运算符，得到的是一个指向数组的指针!!!!这句话尤为重要!也就相当于int (*p) [5] = &a;p是一个指针，它指向的是一个包含5个int元素的数组!那么执行p+1后，p的偏移量相当于 p + sizeof(int) * 5 !
Click here 👆 to get an answer to your question ️ 16: What is the output?#include <stdio.h>int main(){int a[5] = {1,2,3,4,5);int *ptr = (int*)(&a+1);…