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...{ int a[10],i,f; int sum,aver; for(i=0;i<10;i++) scanf("%...
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You're storing eleven numbers into an array of size 10. Thus you're storing the last element out of bounds, which invokes undefined behavior. The reason that this undefined behavior manifests itself as an infinite loop in your case is probably that i is stored after array in memory on your system and when you write a number into array[10] (which is out of bounds, as I said), you're overwriting i.
#include int main(){ // 从键盘输入10个整数，求其平均值 int a[10]; float aver=0; int sum=0; printf("请输入10个整数\n"); for (int i=0;i<10;i++){ scanf("%d",&a[i]); sum=sum+a[i]; aver=sum/10.0; } printf("%f",aver); } 注意：输入第10个数字后，一定要按Enter回车键（按了Enter键才开始计算，虽然 ...
Study with Quizlet and memorize flashcards containing terms like Analyze the following code. double sum = 0; for (double d = 0; d < 10; sum += sum + d) { d += 0.1; }, What is the number of iterations in the following loop: for (int i = 1; i < n; i++) { // iteration }, Analyze the following statement: double sum = 0; for (double d = 0; d<10;) { d += 0.1; sum += sum + d; } and more.
#include main() { int a[10],i,f; int sum,aver; for(i=0;i<10;i++) scanf("%d",&a[i]); sum=0; 我来答
CSDN问答为您找到 本题要求实现一个函数，可求n个数的平均值（函数题）相关问题答案，如果想了解更多关于 本题要求实现一个函数，可求n个数的平均值（函数题） c语言 技术问题等相关问答，请访问CSDN问答。
Analyze the following fragment: double sum = 0; double d = 0; while (d != 10.0) {d += 0.1; sum += sum + d;} c. the program may not stop because of the phenomenon referred to as numerical inaccuracy for operating with floating-point numbers.
在C语言中使用数组必须先进行定义。一维数组的定义方式为：类型说明符 数组名 [常量表达式]；其中：类型说明符是任一种基本数据类型或构造数据类型。数组名是用户定义的数组标识符。方括号中的常量表达式表示数据元素的个数，也称为数组的长度。
文章浏览阅读4.8k次。该程序使用C语言实现，用于计算10名学生的平均成绩。通过输入每个学生的学号、姓名和成绩，程序逐个读取并累加成绩，最后输出平均值。此代码展示了基本的数据结构和输入输出操作。
Analyze the following code. int count = 0; while (count <100){//Point A// System.out.println("Welcome to Java"); count++ //Point B//} //Point C// Correct Answer(s) count < 100 is always true at Point A count < 100 is always false at Point C