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...{ int i,j,n=0; for(i=1;i<=4;i++) { for(j=1;j<=5;j++,
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for (int j = 0; j < n; j++) • j=0 has a cost of 1, j
What is output by the following code? int a = 0;for (int i = 1; i < 5; i++) {for (int j = 1; j < 4; j++) {a++;}}System.out.println(a);
Answer: The output of this code is i=5, j=5. Explanation: In this code there are 2 integer variable is defined (i,j) that's data type is an integer. In the …
Answer to The following code: int i, j; for(i=1;i<=3; i++)
What is the output of the code fragment given below? int i = 0; int j = 0; while (i < 125) {i = i + 2; j++;} System.out.println(j); 63 What is the output of the following code fragment? int i = 1; int sum = 0; while (i <= 15) { sum = sum + i; i++; } System.out.println("The value of sum is " + sum);
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Consider the following segment of C code. int j, n; j = 1; while (j <= n) j=j*2; The number of comparisons made in the execution of the loop for any n > 0 is
Question Time complexity of the following code snippet -: sum = 0; for (int i = 0; i < n; i++) for (int j = 0; j < i*i; j++) for (int k = 0; k < j; k++ ...
5 | 3 | 9 | 20 | elements (n) = 4. after first cycle (i = 0), 20 has reached its correct position within the array (using an ascending order), leaving us with an array of 3 elements to do comparisons to; in next cycle, i will be equal to 1, and as n-1 remains the same, we need to substract 1 in that expression to "shorten" the array: n-1-i = 4 ...