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a⊃2;+2a+1为什么可以转化为3a+2
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Solve an equation, inequality or a system. Example: 2x-1=y,2y+3=x. 1: 2: 3: 4: 5: 6: 7: 8: 9: 0., < > ≤: ≥ ^ √: ⬅: : F _ ÷ | (* / ⌫ A: ↻: x: y = +-G
If α and β roots of equation px^2 - qx - r = 0, then find the equation which has roots 1/α and 1/β asked Apr 30, 2020 in Complex Numbers by PritiKumari ( 48.0k points) complex numbers
& is "valid", though whether you want to use it is another question. If you're writing a document in XML, then & will be used to represent an ampersand. If your XML document is describing content that itself is encoded in a similar way -- e.g. HTML -- then that content could logically include an & itself. This could lead to a & in the XML.
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If the circles (x + 1) 2 + (y − 1) 2 = 4 a 2 and x 2 + y 2 − 4 x + 6 y − 3 = 0 have three common tangents only, then the value of the expression a 2 − 2 a + 3 4, is View Solution Q 4
Use Cauchy-Schwarz on the vectors $$\mathbf{x} = (1, \sqrt{2}, \sqrt{3}, \dots, \sqrt{20})$$ and $$\mathbf{y} = (1a_1, \sqrt{2}a_2, \sqrt{3}a_3, \dots, \sqrt{20}a_{20})$$
The solution to the equation 2 + 3(2a + 1) = 3(a + 2) is a = 1/3. Let's solve the equation: 2 + 3(2a + 1) = 3(a + 2) First, distribute the constants outside the parentheses: 2 + 6a + 3 = 3a + 6 . Next, combine like terms by subtracting 3a from both sides of the equation: 6a - 3a + 2 + 3 = 6 . This simplifies to: 3a + 5 = 6 . Now, subtract 5 ...
For example, if we had the expression 5 (2 b 2 + 3 b − 4), we would multiply as follows: 5 × 2 b 2 + 5 × 3 b + 5 × (− 4), resulting in 10 b 2 + 15 b − 20. The steps shown are based on the distributive property of multiplication, which states that a ( b + c ) = ab + a c .
原式=(a^3-a)+(a^2-2a-1)=a(a-1)(a+1)+(a-1)^2=(a-1)[a(a+1)+(a-1)]=(a-1)(a^2+2a-1) 引申：初中数学教材中主要介绍了提公因式法、公式法。 当然也要掌握：拆项和添减项法，分组分解法和十字相乘法，待定系数法，双十字相乘法，对称多项式，轮换对称多项式法，余式定理法 ...
A jadi disini kita tahu karena salah satu akarnya adalah 2 berarti 2 dikalikan dengan x2 x3 up di mana Nggak tahu bahwa dirinya ini adalah suatu konstanta yaitu - 6 - 26 bulan adalah 1/6 dibagi 16 x akar lain yang berarti anda X2 dengan X3 maka kita dapati bahwa x 2 * x 3 = 6 dibagi dengan 2 pangkat 6 dibagi 23 jadi disini kita tahu bahwa hasil ...