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#include <stdio.h> main(){int a[]={1,2,3,4,5,6,7,8,9,0},*p; p...
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I have been trying to understand the output of this program: #include int main(){ static int arr[] = {0, 1, 2, 3, 4}; int *p[] = {arr, arr+1, arr+2, arr+3 ...
1. What will be the output of following program? #include int main() { int a = 5, *b, c; b = &a; printf("%d", a * *b * a + *b); return (0); } Options: 1 ...
Consider the C program given below. What does it print? #include int main () { int i, j; int a [8] = {1, 2, 3, 4, 5, 6, 7, 8}; for(i = 0; i < 3; i++) { a[i ...
Concept: a = address of 0 th index of 2D array i.e address of 1D array {1,2,3,4,5}. *a = address of 0 th index element of 0 th index of above array i.e address of ...
a is 3D array with size [3][3][3] Therefore each 2D array contains 9 elements, we have 3 such arrays. 0th 2D array have {1,2,3,4,5,6,7,8,9} 1st 2D array have {10,11,12,13,14,15,16,17,18}
Example 1: C Output #include int main() { // Displays the string inside quotations printf("C Programming"); return 0; } Output. C Programming ... To use printf() in our program, we need to include stdio.h header file using the #include statement. The return 0; statement inside the main() function is the "Exit status" of the ...
#include main() {char a[10]={9,8,7,6,5,4,3,2,1,0},*p=a+5; printf("%d",*--p); }看不懂啊， 我来答
It does not work. Try replacing "int *p;" with "int *p = NULL;" and it will try to dereference a null pointer. This is because fun() makes a copy of the pointer, so when malloc() is called, it is setting the copied pointer to the memory location, not p. p is pointing to random memory before and after the call to fun(), and when you dereference it, it will crash.
#include int main() { int a[] = { 1,2,3,4,5 }; int *p = (int *)(&a + 1); int *q = &a[0] + 1; printf("%d", *(p - 1)); printf("%d", *(q - 1)); return 0 ...
It should be #include .. The problem is that <> is replaces eith <> and it isn't replaced back. < is the HTML escape of < and > is the HTML escape of >. In order to prevent XSS, it may got replaced one time too much. E.g. the author wanted to use the HTML escape but the XSS protection escaped the escape and your browser undid the escape only once.