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#include <stdio.h> void main() { int a[3][3]={{1,2},{3,4},{5...
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I'm learning C language and stuck with a question as follows: #include #include void main() { short int a=5; clrscr(); printf("%d"+1,a); getch ...
Options: 1. 130 2. 103 3. 100 4. 310 The answer is the option(1). Explanation: Here the expression a**b*a + *b uses pointer in C/C++ concept. Here a**b*a + *b means 5*(value of pointer b that is 5)*5 +(value at pointer b which is 5 again).
All valid C programs must contain the main() function. The code execution begins from the start of the main() function. The printf() is a library function to send formatted output to the screen. The function prints the string inside quotations. To use printf() in our program, we need to include stdio.h header file using the #include
It does not work. Try replacing "int *p;" with "int *p = NULL;" and it will try to dereference a null pointer. This is because fun() makes a copy of the pointer, so when malloc() is called, it is setting the copied pointer to the memory location, not p. p is pointing to random memory before and after the call to fun(), and when you dereference it, it will crash.
Answer to #include void main() { int. Your solution's ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.
Consider the following $\\mathrm{C}$ program: #include <stdio.h> void fX (); int main ... output The program will terminate with $1234$ as output
#include #include int main() {printf("Hello, World!\n"); ... 4 C generics, void *, function pointers 5 Floating point representation, intro to assembly 6 x86-64: addressing, ALU ops Midterm: Thu Feb 8th, Evening 7 x86-64: control, function calls, runtime stack
Consider the following C program. #include <stdio.h> int main () { int a[4] [5] = {{1, 2, ... return(0); } The output of the program is _______.
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Consider the following C code: #include<stdio.h> int *assignval (int *x, int val) ... compiles successfully but execution may result in memory leak.