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#include "stdio.h" main() { int a []={1,2,3,4,5},*p;p=a;*(p+2
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I am trying to do a project in C but I have problems with the string #include, I tried several tutorials but none of them worked, my code: #include int main () {
Answer : 8 5 5 Description : First size of character pointer is printed which is 8 on the machine this program is run. Then the size of string str2 whose size is 5 (including the '/0' termination character) is printed. The third is similar to second one. Question 4 What will be output of the following c program?
Consider the following C program. Assume parameters to a function are evaluated from right to left. #include int g(int p) { printf("%d", p); return p; } int h(int q) { printf("%d", q); return q; } void f(int x, int y) { g(x); h(y); } int main() { f(g(10), h(20)); } Which one of the following options is the CORRECT output of the above C program? 20101020 10202010 20102010 10201020
Example If we use #include in your c program, it will include stdio.h file into our source program which has the information for all input, output related functions.
code: #include int main () { int arr [4] [5]; int i, j; for (i =0; i<4; i++) { for (j =0; j<5; j++) { arr [i] [j] = 10 +i + j; } } print ("%d", * (arr [1] + 9)); return 0; } Key Points C doesn't check array boundaries. A segmentation fault will only occur if you try to dereference a pointer to memory that your program doesn't have permission to access. Simply going past the end of an ...
C Programming questions and answers section on "C Preprocessor Find Output of Program" for placement interviews and competitive exams: Fully solved C Programming problems with detailed answer descriptions and explanations are given for the "C Preprocessor Find Output of Program" section.
Output: x=21 y=504 z=504 Description: In the beginning, the address of x is assigned to y and then y to z, it makes y and z similar. when the pointer variables are incremented their value is added with the size of the variable, in this case, y and z are incremented by 4. Question 5 What will be the output?
The main thing to consider is the arithmetic operation on the the pointer. Do the following ie add + 1 = add + 1*(size of the data type of the data which is pointed by that address)
Consider the following C program. #include int main () { int a [4] [5] = { {1, 2, ... return (0); } The output of the program is _______.
9 y = --x means "decrease x by one, then store the result in y" z = x-- means "save a temp of x. Decrease x by one. Store the temp value in z" Hence: x starts at 4. It gets decreased by 1 (to 3). 3 is stored in y. x is saved to a temp. x is decreased again (to 2). then the temp (3) is stored in z. y and z are printed as 3, x is printed as 2.