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...$B$1:$B$1000=$J$1,ROW($B$1:$B$1000),4^8),ROW(A1)))&&
"相关结果约100,000,000个
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4.row（A1):返回的结果是第一行的行号，也就是等于1。当向下复制时，会变成row(A2),row(A3)等，返回2，3等，一般用作取序号。
\begin{align*} x_1 - x_2 +3x_3 +2x_4 = b_1 \\ -2x_1 + x_2 +5x_3 + x_4 = b_2 \\ -3x_1 + 2x_2 + 2x_3 - x_4 = b_3 \\ 4x_1 -3x_2 + x_3 + 3x_4 = b_4 \end{align*} linear-algebra; matrices; systems-of-equations; Share. Cite. ... You should reduce the matrix to row reduced echelon form just to be sure! Then you can read the solutions to this equation ...
j=1 j!= s A rjx j +A rsx s for x s gives x s = 1 A rs y r +!n j=1 j!= s −A rj A rs x j = B rsy r + n j=1 j!=s B rjx j, (2.4) where B rs = 1 A rs,B rj = −A rj A rs ∀j != s. (2.5) These formulae define the rth row B r· of the transformed tableau. We can express them in MATLAB by first defining J to represent the columns of the tableau ...
Explicitly write (j = 1, m'\Jylj = 1,m) in 3 x 3 matrix form. (b) Show that for j = 1 only, it is legitimate to replace e-iJy B IN by 1-i Jy ħ sin B - -6) )a- (1 - cos B). (c) Using (b), prove do=1}(B)= (1) (1 +cos B) -() sin B (1 - cos B) (a)s -(12) (1)(1 - cos B) - cos B) (2) sin B (+)(1+cos B) sin B cos B sin B ...
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If A and B are square matrices of order 3 such that `absA=-1,absB=3," then "abs(3AB)` equals asked Apr 17, 2022 in Matrices by Shwetapandey ( 122k points) class-12
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If n(A) = 1000, n(B) = 500, n(A $$\cap$$ B) $$\ge$$ 1 and n(A $$\cup$$ B) = P, then. A. 500 $$\le$$ P $$\le$$ 1000. B. 1001 $$\le$$ P $$\le$$ 1498. C. 1000 $$\le$$ P $$\le$$ 1498. D. 1000 $$\le$$ P $$\le$$ 1499. Check Answer. PREVIOUS. Questions Asked from Sets and Relations (MCQ (Single Correct Answer))
If A = \\(\\sum\\limits_{j=1}^{10}\\sum\\limits_{i=1}^{10}\\) min(i, j), B = \\(\\sum\\limits_{i=1}^{10} ... equal to (1) 1000 (2) 1100 (3) 1200 (4) 1190