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...main() { int a,b,c,d,e; printf("please enter a,b,c,d :\n...
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Answer to Consider the program #include main () { int a,b,c,d;
In this tutorial, you will learn to use scanf () function to take input from the user, and printf () function to display output to the user with the help of examples.
There are only two arguments to your printf call: "%d %d %d" and the result of evaluating (a,b,c). The result of (a,b,c) is just the last item in the list: c, which is 5. That's passed to printf, which displays 5 for the first %d. Since there are no more arguments, the remaining %d's just display whatever garbage is sitting on the call stack, resulting in the strange values you see.
Every C program coded to run in a hosted execution environment contains the definition (not the prototype) of a function named main, which is the designated start of the program.
The main function is the entry point of a C program. It is a user-defined function where the execution of a program starts. Every C program must contain, and its return value typically indicates the success or failure of the program. In this article, we will learn more about the main function in C. Example:
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C program is given below: # include int main () { int i, j; char a [2] [3] = {{'a', 'b', 'c'}, {'d', 'e', 'f'}}; char b [3] [2]; char *p = *b; for (i = 0; i < 2; i++) { for (j = 0; j < 3; j++) { *(p + 2*j + i) = a [i] [j]; } } }
The following is a template for reading two integers a and b, and printing the product c = a x b. #include &lt;stdio&gt; void main () { int a, b, c; printf (&quot;Enter an integer:\n&quot;); scanf (&quot;%d&quot;, &amp;a); printf (&quot;Enter an integer:\n&quot;); scanf ...
Explanation: In this program, the format specifier %d is used to print integers variables using printf. Here, it prints the values of a, b, and the result of a + b.
举报 黑色幽默002 2010-05-10 · 超过11用户采纳过TA的回答 关注 答案是6 关系到运算的优先级 先判断a是否大于b 因为5>4所以在运算a>c?a:c 5<6所以结果是6 3 评论 分享