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...main() { int a=2,b=8; while(b--<0) b-=a ; a++ ;
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int main() { int a = 5, *b, c; b = &a; printf("%d", a * *b * a + *b); return (0); } Options: 1. 130 2. 103 3. 100 4. 310. The answer is the option(1). Explanation: Here the expression a**b*a + *b uses pointer ... We know that a++ is post increment and in post-increment we first assign then increment.when first time while loop execute, while(0<5 ...
Ideally you should not define your function in main(). However if you do, first define it and then use it. Also the return type of change function should be void as this function is not returning anything and if you don't specify the return type the default is int. Change change ( int *b, int n ) to void change ( int *b, int n ).
Solution(By Examveda Team) Step 1: Initialize a with the value 10. Step 2: Declare b without initialization (the initial value is undefined). Step 3: Evaluate a++ (post-increment): - The current value of a is 10. - After evaluating a++, a becomes 11. Step 4: Evaluate ++a (pre-increment): - ++a increments a to 12 and returns the updated value, which is 12. Step 5: Sum the values obtained in ...
Step 1: int i = 0; here variable i is an integer type and initialized to '0'. Step 2: for(; i<=5; i++); variable i=0 is already assigned in previous step. The semi-colon at the end of this for loop tells, "there is no more statement is inside the loop". Loop 1: here i=0, the condition in for(; 0<=5; i++) loop satisfies and then i is incremented by '1'(one) ...
Step 1: int a, b=3; The variable a and b are declared as an integer type and varaible b id initialized to 3. Step 2: a = CUBE(b++); becomes => a = b++ * b++ * b++; => a = 3 * 3 * 3; Here we are using post-increement operator, so the 3 is not incremented in this statement. => a = 27; Here, 27 is store in the variable a. By the way, the value of ...
QUE.1 What will be output if you will compile and execute the following c code? #include int main() { int a = 5; float b; printf("%d ", sizeof(++a + b)); printf("%d ", a); return 0; } (a)2 6 (b)4 6 (c)2 5 (d)4 5 Answer : d Explanation: ++a +b = 6 + Garbage floatin
Answer to int main (void) { int a = 2; int b = 6; while. To determine the output of the given code, start by initializing the variables ( a = 2 ) and ( b = 6 ), and then check the condition of the while loop to proceed.
Consider the following C program: C #include int main() { int a[] = {2, 4, 6, 8, 10}; int i, sum = 0, *b = a + 4; for (i = 0; i < 5; i++ ) sum = sum + (*b ...
What is the output when the sample code below is executed? void fun1(int a,int b) {a++; b++;} main() {int x=5,y=10; fun1(x,y); printf("%d %d",x,y); return 0;} A. 11 6 B. 10 5 C. 5 10 D. 6 11 C Why hexadecimal and octal representations are used for sets of bits?
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