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Because W=F*s so how can W=mgh/t be the value of W? Q. A ball is thrown vertically upwards, it reaches the height h and then returns to the initial position. Work done by gravity when ball moves upwards is W 1 and W 2 when ball moves in downward direction. Then. Q.
Calculate the unknown variable in the equation for gravitational potential energy, where potential energy is equal to mass multiplied by gravity and height; PE = mgh. Calculate GPE for different gravity of different enviornments - Earth, the Moon, Jupiter, or specify your own. Free online physics calculators, mechanics, energy, calculators.
At a start, the potential energy = mgh and kinetic energy = zero because its velocity is zero. Total energy of the object = mgh. As it falls, its potential energy will change into kinetic energy. If v is the velocity of the object at a given instant, the kinetic energy = 1/2mv 2.
f(x)-. = + Go. Steps Graph Related Examples. Generated by AI. AI explanations are generated using OpenAI technology. AI generated content may present inaccurate or offensive content that does not represent Symbolab's view. ... F=MGH. en. Related Symbolab blog posts. Practice, practice, practice. Math can be an intimidating subject. Each new ...
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Find an answer to your question if f=mgh. what is f ? srr1993pe4gy8 srr1993pe4gy8 24.11.2018 Physics Secondary School answered • expert verified If f=mgh. what is f ? See answers Advertisement Advertisement Brainly User Brainly User ...
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solve F = MGH for H, H= I really have no clue on this one please help. Added by Daniel G. Instant Answer. Step 1. The given equation is: \[ F = MGH \] and we need to solve for \( H \). Show more… Show all steps. Solved by Verified Expert Vysakh M on 06/20/2022 ...
The expression for the H would be as; H = F/MG. What is an expression? Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.. The Numbers constants, variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbol; which can also be used to ...
No, first of all F=mgh is not true as you have mixed the gravitational force with the gravitational potential energy. Second, you are mixing two things. E=mgh is an approximation which is valid as long as the gravitational field g is homogeneous. If you are working at the scale where F=MmG/r^2, this is no longer the case.