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int[4][3]={1,2,3,4,5,6,7,8,9,10,11,12},(*prt)[3]=a,*p=a[0]; a...
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otherwise int *a2={0,1,2,3,4,5,6,7,8,9} a2 is a pointer (and i think you can't initialize it like that), and even if you do a2 = a1 the memory is still 'owned' by a1. You can see that a1 and a2 are different types by using sizeof . a2 is only size of a pointer, while a1 is sizeof(int) * 10
Extra Info that i want to add: Here &x means address of whole 2-d array though it will show same address as x or *x or &(x[0][0]), *(&x) is same as (&x[0]) which is base addr. of whole array of 3 elements which is same as x and *x is equal to **(&x) which is same as &(x[0][0]) which address of first element of 3 element array.
prt[1][2]： prt 是指向 a 数组的指针，因此 prt+1 表示指向第二行的指针， prt[1] 表示第二行的首元素指针， prt[1]+2 表示第二行第三个元素的指针， prt[1][2] 表示第二行第三个元素的值。
a is 3D array with size [3][3][3] Therefore each 2D array contains 9 elements, we have 3 such arrays. 0th 2D array have {1,2,3,4,5,6,7,8,9} 1st 2D array have {10,11,12,13,14,15,16,17,18}
Consider the following C program. #include int main { int a[4] [5] = {{1, 2, 3, 4, 5}, {6, 7,8, 9, 10}, {11, 12, 13, 14, 15}, {16, 17,18, 19, 20}}; printf ...
这是一个指针求值的问题，答案应该是A 答案分析如下： 首先，所有的逗号运算符，是从左向右进行的，其值为右边结果计算的值 A p+=2,*(p++) 先计算p+=2 再计算*p 最后计算p++ 表达式的值在第二步计算确定的 为p[2] = a[2] = 3。 表达式计算完毕之后，p指向4
d 选项 二维数组名 a 指向的是第一行（1，2，3）这个小数组，a+1，编译一个整数组的，变为指向第二行4，5，6。 *（a+1） 指向的是第二行数组里的首个元素的地址也就是4，此时再偏移两个单位，指向了6，最外层再解引用，得到6.
设有以下定义: int a[4][3]={1,2,3,4,5,6,7,8,9,10,11,12}; int (*prt)[3]=a,*p=a[0] 则下列能够正确表示数组元素a[1][2]的表达式是 时间: 2023-10-09 21:08:00 浏览: 778 下列能够正确表示数组元素a[1][2]的表达式是： 1. *(prt+1)+2 2. *(*(prt+1)+2) 3. *(p+1*3+2) 4. *(p+4)+2 其中，选项1和2是指针运算 ...
设有以下定义:int a[4][3]={1,2,3,4,5,6,7,8,9,10,11,12};int (*prt)[3]=a,*p=a[0];则下列能够正确表示数组元素a[1][2]的表达式是 A. *((*prt+1) [2]) B ...
Study with Quizlet and memorize flashcards containing terms like A two-dimensional array arr is to be created with the following contents. boolean[][] arr = {{false, true, false}, {false, false, true}}; Which of the following code segments can be used to correctly create and initialize arr ?, Consider the following code segment, which is intended to declare and initialize the two-dimensional ...