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main() {int a=0,i; for(i=1;i<5;i++) { switch(i) { case0: case3:a...
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你先问什么啊？这个程序有明显的没有错误啊!但是要心中的功能可能有点不如意吧，比如说i=3的时候，它会执行a+=2,接着会执行后面的a+=3这条语句，要想实现你的匹配就必须加个break。
Forget about the ++ for the moment, they're just a distraction.. int a = 5; int i = 0; int x = (i, a); Sets the value of x to 5. The i is evaluated and discarded, then the a is evaluated and assigned to x.. In your loop, the post-increment a++ does what it always does; returns the current value and then increments the variable. So x takes the value of a before it is incremented, then a's value ...
// for_statement5.cpp int main(){ int i = 0; // hidden by var with same name declared in for loop for ( int i = 0 ; i < 3; i++ ) {} for ( int i = 0 ; i < 3; i++ ) {} } This behavior more closely mimics the standard behavior of a variable declared in a for loop, which requires variables declared in a for loop to go out of scope after the loop is ...
Since case 0 is true i becomes 5, and since there is no break statement till last statement of switch block, i becomes 16. ... Question 1 [GFGTABS] CPP #include int main() { int i; for (i = 0; i<5; i++) { int i; i = 10; printf("%d ", i) ; } return 0; } [/GFGTABS]Output10 10 10 10 10 Explanation: Here, it would seem that, as 'i' got ...
Step 1: int i = 0; here variable i is an integer type and initialized to '0'. Step 2: for(; i<=5; i++); variable i=0 is already assigned in previous step. The semi-colon at the end of this for loop tells, "there is no more statement is inside the loop". Loop 1: here i=0, the condition in for(; 0<=5; i++) loop satisfies and then i is incremented by '1'(one) ...
Explanation: This will not print anything because it will not enter the for loop. What is written between ; and ; is called the condition. When you write a condition there, like in or i==n, etc., it is either false or true.
//先改正如下： #include void main() {int i; for(i=1;i<=5;i++) switch(i%5) {case 0: printf("*");break; case 1:printf("#");break; default:printf("\n");
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for(int i = 0; a[i]; i++) has the same meaning as for(int i = 0; a[i] != 0; i++), which means "enter the loop until the element a[i] gets 0; if a is a string, then this means "enter the loop until a[i] points to the string terminating character \0. Note, however, that C++ offers other ways of iterating through the characters of a string, like, for example, for (auto c : a) { cout << c << endl; }
Given the following program: #include using namespace std; int main() { int i; int value 3; for (i = 0; i < 5; i++) value value * (i + 1) + i; cout << "value T! << value << endl; return 0; } Rewrite the program and use while loop instead of the for loop. The new program should have the same output.