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main( ) %7Bint i,j,m,n; i=8;j=10; m= i;n=j ; printf("%d,%d,%d...
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should be int main() and the '\n' in printf should be at the end - pmg. Commented Oct 8, 2010 at 14:00. ... y=3 and z = 3 z = x--; printf ("\n %d %d %d", x,y,z); } Share. Improve this answer. Follow edited Oct 8, 2010 at 15:06. answered Oct 8, 2010 at 14:09. Pavan Pavan. 18.6k 10 10 gold badges 62 62 silver badges 100 100 bronze badges. 12 ...
Answer : 7, 224, 0 Description : As x = 7 so first %d gives 7, second %d will take value of x after left shifting it five times, and shifting is done after converting the values to binary, binary value of 7 (000111) will be left shifted twice to make it binary 224(11100000), so x<<5 is 224 and as left shifting does not effect the original value of x its still 5 so third %d will also show 0.
C Programming questions and answers section on "Control Instructions Find Output of Program" for placement interviews and competitive exams: Fully solved C Programming problems with detailed answer descriptions and explanations are given for the "Control Instructions Find Output of Program" section - Page 4.
printf函数在打印的时候先会计算出后面所有的表达式后再输出到标准输出上，后面的逗号表达式为i,j,m=++i,n=j++;i初始化为8，j初始化为10，m=++i(i先加变为9赋值给m，所以i为9，m为9)，n=j++（j先赋值后再加，所以n是10，j也是10）。 也许你会问j加了为什么不是11，这取决你的编译器（i++，和++i）在什么时候 ...
你首先要搞懂++在变量前后的含义 ++在变量前,例如++i,就是先i自加,然后再去做运算 ++在变量后,例如i++,就是先做运算,然后再将i自加 m=++i 这个意思是将先将i自加,然后再将i的值赋给m n=j++ 这个意思就是j的值赋给n,然后j自加 这样算下来的结果就是i=9 j=11 m=9 n=10
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定义了个整型变量：i、j、m、n，并初始化i为8，j为10。 2. 执行m+=i++，先将i的值8赋给m，然后i自增1，此时i的值为9，m的值为8。 3. 执行n-=--j，先将j自减1，此时j的值为9，然后将j的值9赋给n，此时n的值为9。 4. 使用printf函数输出结果，格式化输出i、j、m、n的值。 5.
Step 1: int i=-3, j=2, k=0, m; here variable i, j, k, m are declared as an integer type and variable i, j, k are initialized to -3, 2, 0 respectively.. Step 2: m = ++i && ++j && ++k; becomes m = -2 && 3 && 1; becomes m = TRUE && TRUE; Hence this statement becomes TRUE. So it returns '1'(one). Hence m=1. Step 3: printf("%d, %d, %d, %d\n", i, j, k, m); In the previous step the value of i,j,k are ...
主要看printf（）,执行顺序，一般主流编译器都是从左向右的 m=++i 后 i =9;m=9; n=j++;后 j=11;n=10; 主要搞清楚 m=++i和m=i++的区别
Step 4: j = a[1]++; becomes j = 2++; Hence j = 2 and a[1] = 3. Step 5: m = a[i++]; becomes m = a[2]; Hence m = 15 and i is incremented by 1(i++ means 2++ so i=3) Step 6: printf("%d, %d, %d", i, j, m); It prints the value of the variables i, j, m. Hence the output of the program is 3, 2, 15